how can position a comma in a number-CodePudding

I have a variable of a df which contains numbers, but I need to transform it into decimals

An example:

[1]  NA  NA  NA 595 595   5

so I need to create a new variable or transform it to get the following form

[1]  NA NA NA 5.95 5.95 5.0

but I haven't find a way to do this, I'll appreciate any help

I have looking ways, but the only thing I find is a stata command

destring v1, g(new_var) dpcomma
     drop v1

and I don't understand it

result from str

num [1:308535] NA NA NA 595 595 5 625 645 59 54 ...

an extract from dput

515, 555, 478, 665, 635, 555, 608, 578, 633, 62, 59, 608, 498, 
603, 54, 638, 565, 625, NA, 545, 613, 573, 543, 653, 523, 568, 
508, 635, 625, 598, 62, 565, 545, 655, 628, 52, 588, 598, 55, 
598, 55, 578, 515, 64, 54, 54, 625, 565, 608, 588, 618, 535, 
603, 663, 558, 638, 59, 518, 54, 613, 495, 535, 51, 543, 613, 
583, 58, 593, 498, 568, 538, 525, 653, 555, 588, 56, 505, 54, 
618, 56, 623, 508, 595, 6, 585, 518, 545, 525, 603, 588, 575, 
568, 568, 588, 595, 593, 565, 535, 563, 643, 57, 645, 608, 608, 
555, 57, 54, 555, 61, 528, 623, 653, 618, 528, 563, 63, 538, 
52, 563, 51, 538, 525, 558, 568, NA, 523, 623, NA, 603, 555, 
48, 633, 575, 583, 54, 578, 56, 65, 525, 5, 595, 663, 618, 59, 
603, 525, 54, 555, 625, 528, 538, 67, 64, 528, 623, 615, 565, 
548, 65, 508, 653, 63, 58, 553, 553, 548, 575, 553, 538, 583, 
565, 613, 608, 68, 55, 605, 675, 585, 533, 565, 515, 525, 568,

CodePudding user response：

Something like this should work (this assumes your input is never 0, if this can happen you need to set Inf values to 0 at the end of the process):

# first define a function that will to the job
toRate <- function(x) {      

  # get number of digits minus one
  ndigits <- ceiling(log10(abs(x))) - 1 # or use floor and skip the -1
  # divide by a power of 10 according to number of digits
  y <- x / (10^ndigits)


  return(y)
}

original <- c(515, 555, 478, 665, 635, 555, 608, 578, 633, 62, 59, 608, 498, 
603, 54, 638, 565, 625, NA, 545, 613, 573, 543, 653, 523, 568, 
508, 635, 625, 598, 62, 565, 545, 655, 628, 52, 588, 598, 55, 
598, 55, 578, 515, 64, 54, 54, 625, 565, 608, 588, 618, 535, 
603, 663, 558, 638, 59, 518, 54, 613, 495, 535, 51, 543, 613, 
583, 58, 593, 498, 568, 538, 525, 653, 555, 588, 56, 505, 54, 
618, 56, 623, 508, 595, 6, 585, 518, 545, 525, 603, 588, 575, 
568, 568, 588, 595, 593, 565, 535, 563, 643, 57, 645, 608, 608, 
555, 57, 54, 555, 61, 528, 623, 653, 618, 528, 563, 63, 538, 
52, 563, 51, 538, 525, 558, 568, NA, 523, 623, NA, 603, 555, 
48, 633, 575, 583, 54, 578, 56, 65, 525, 5, 595, 663, 618, 59, 
603, 525, 54, 555, 625, 528, 538, 67, 64, 528, 623, 615, 565, 
548, 65, 508, 653, 63, 58, 553, 553, 548, 575, 553, 538, 583, 
565, 613, 608, 68, 55, 605, 675, 585, 533, 565, 515, 525, 568)
df <- cbind.data.frame(original = original)
df$new <- toRate(df$original)

Output:

df$new
[1] 5.15 5.55 4.78 6.65 6.35 5.55
  [7] 6.08 5.78 6.33 6.20 5.90 6.08
 [13] 4.98 6.03 5.40 6.38 5.65 6.25
 [19]   NA 5.45 6.13 5.73 5.43 6.53
 [25] 5.23 5.68 5.08 6.35 6.25 5.98
 [31] 6.20 5.65 5.45 6.55 6.28 5.20
 [37] 5.88 5.98 5.50 5.98 5.50 5.78
 [43] 5.15 6.40 5.40 5.40 6.25 5.65
 [49] 6.08 5.88 6.18 5.35 6.03 6.63
 [55] 5.58 6.38 5.90 5.18 5.40 6.13
 [61] 4.95 5.35 5.10 5.43 6.13 5.83
 [67] 5.80 5.93 4.98 5.68 5.38 5.25
 [73] 6.53 5.55 5.88 5.60 5.05 5.40
 [79] 6.18 5.60 6.23 5.08 5.95 6.00
 [85] 5.85 5.18 5.45 5.25 6.03 5.88
 [91] 5.75 5.68 5.68 5.88 5.95 5.93
 [97] 5.65 5.35 5.63 6.43 5.70 6.45
[103] 6.08 6.08 5.55 5.70 5.40 5.55
[109] 6.10 5.28 6.23 6.53 6.18 5.28
[115] 5.63 6.30 5.38 5.20 5.63 5.10
[121] 5.38 5.25 5.58 5.68   NA 5.23
[127] 6.23   NA 6.03 5.55 4.80 6.33
[133] 5.75 5.83 5.40 5.78 5.60 6.50
[139] 5.25 5.00 5.95 6.63 6.18 5.90
[145] 6.03 5.25 5.40 5.55 6.25 5.28
[151] 5.38 6.70 6.40 5.28 6.23 6.15
[157] 5.65 5.48 6.50 5.08 6.53 6.30
[163] 5.80 5.53 5.53 5.48 5.75 5.53
[169] 5.38 5.83 5.65 6.13 6.08 6.80
[175] 5.50 6.05 6.75 5.85 5.33 5.65
[181] 5.15 5.25 5.68

CodePudding user response：

You could do:

x/10^(nchar(x) - 1)

 [1] 5.15 5.55 4.78 6.65 6.35 5.55 6.08 5.78 6.33 6.20 5.90

CodePudding user response：

Another option is to insert a . after the first character with stringr::str_sub then convert back to numeric.

x <- c(515, 555, 478, 665, 635, 555, 608, 578, 633, 62, 59)

stringr::str_sub(x, 2, 1) <- "."

as.numeric(x)

#----

[1] 5.15 5.55 4.78 6.65 6.35 5.55 6.08 5.78 6.33 6.20 5.90

Or with base function sub

as.numeric(sub("^(.{1})", "\\1\\.", x))