How to return a list the last vertex within each path object?-CodePudding

I am trying to build a chaining mechanism with my query and I want to start my next invocation from the end of the previous. I've tried using the by step, but I can't seem to get it to work or do what I would like. What is the best way to get the last vertex in all the paths from the below query?

g.V(1).repeat(out()).times(2).emit().path();

If this returned:

[v[1], v[2], v[3]]
[v[1], v[3], v[4]]

All I want is:

v[3]
v[4]

Thanks!

CodePudding user response：

You can take the tail of a path

gremlin> g.V(44).out().out().limit(5).path()
==>[v[44],v[8],v[47]]
==>[v[44],v[8],v[48]]
==>[v[44],v[8],v[49]]
==>[v[44],v[8],v[51]]
==>[v[44],v[8],v[52]]

gremlin> g.V(44).out().out().limit(5).path().tail(local)
==>v[47]
==>v[48]
==>v[49]
==>v[51]
==>v[52]