Discord.py divide commands in multiple files [SOLVED]-CodePudding

I've been trying to make a discord.py bot, but all the commands are in one unique file. Is there any way that I can divide the commands in various .py files? For example: in the main.py file I have

from discord.ext import commands
import discord, os, random, time, keep_alive, save
from discord.utils import get
from discord import Member

TOKEN = os.environ['DISCORD_TOKEN']

JOIN_ROLE = "Unverified"

prefix = "/"


intents = discord.Intents.all()
bot = commands.Bot(prefix, intents = intents)

bot.remove_command('help')


keep_alive.keep_alive()
bot.run(TOKEN)`

and in another file named help.py I have this:

@bot.command()
async def help(ctx):
  embed = discord.Embed(title="Help commands", description="Shows various help commands")
  embed.add_field(name="Show this help", value = "`/help`", inline = False)
  embed.add_field(name="Help random stuff", value="`/helprand`", inline=False)
  embed.add_field(name="Help economy", value="`/helpeco`", inline=False)
  embed.add_field(name="Help music", value = "`/helpmusic`", inline = False)
  await ctx.send(embed=embed)

is there any way with which I can link these 2 files, so that when I type /help it pops up the help command instead of giving me an error?

Thanks to everyone that will help me

CodePudding user response：

You can use cogs

For example, in help.py, you create a class which inherits from commands.Cog and contains a commands.command:

import discord
from discord.ext import commands

class HelpCog(commands.Cog):
    def __init__(self, bot):
        self.bot = bot
    
    @commands.command()
    async def help(self, ctx):
        embed = discord.Embed(title="Help commands", description="Shows various help commands")
        embed.add_field(name="Show this help", value = "`/help`", inline = False)
        embed.add_field(name="Help random stuff", value="`/helprand`", inline=False)
        embed.add_field(name="Help economy", value="`/helpeco`", inline=False)
        embed.add_field(name="Help music", value = "`/helpmusic`", inline = False)
        await ctx.send(embed=embed)

and then in your main file, you add the HelpCog to your bot:

from help import HelpCog
...
bot = commands.Bot(prefix, intents = intents, help_command=None)
bot.add_cog(HelpCog(bot))

and remove the following line, because it's better to remove the default help command in the initialization of the commands.Bot:

bot.remove_command("help")

CodePudding user response：

I don't know about specific discord development, but in standard python parlance, what you are describing is the difference between modules and packages. e.g.

This:

# foo.py
def bar():
    print("bar")

def baz():
    print("baz")

Would be imported similarly to:

# foo/__init__.py
from foo.bar import bar
from foo.baz import baz

# foo/bar.py
def bar():
    print("bar")

# foo/baz.py
def baz():
    print("baz")

Where in both cases you could import as from foo import bar, baz.