The same name, for example, in the title column in random assignment for worker or a doctor, a, how do I use python implementation?

CodePudding user response:

Import the random
The import pandas as pd
S=pd. DataFrame ([[' zhang ', ' '], [' bill ', ' '], [' Cathy ', ' ']], the columns=[' name ', 'title'])
Print (s)
S [' title ']=[' title '] s map (lambda x: the random choice ([" doctor ", "workers", 'students']))
Print (s)

CodePudding user response:

But you have the same name will randomly to different titles, I want to name the same title

CodePudding user response:

 import pandas as pd 
Df=pd DataFrame ([[' zhang ', ' '], [' bill ', ' '], [' Cathy ', ' '], [' zhang ', ' '], [' Cathy ', ' ']], the columns=[' name ', 'title']) 

L=[" doctor ", "workers", 'students',' civil servants'] 
Df [' title ']=df [' name ']. The map (lambda x: l [int (x.e ncode (" utf-8 "), hex (), 16) % 4]) 
Print (df) 

CodePudding user response:

That is better to do,

 import random 
The import pandas as pd 
S=pd. DataFrame ([[' zhang ', ' '], [' bill ', ' '], [' Cathy ', ' '], [' zhang ', ' ']], the columns=[' name ', 'title']) 
Print (s) 
Names=list (the set (s) [r]. 'name' tolist ())) 
Print (names) 
Dict1=dict (zip (names, the list (random. Choice ([" doctor ", "workers", 'students']) for _ in names))) 
Print (dict1) 
S [' title ']=[' name '] s map (lambda x: dict1 [x]) 
Print (s) 

CodePudding user response:

The

reference 4 floor weixin_45903952 reply:

that is better to do,

 import random 
The import pandas as pd 
S=pd. DataFrame ([[' zhang ', ' '], [' bill ', ' '], [' Cathy ', ' '], [' zhang ', ' ']], the columns=[' name ', 'title']) 
Print (s) 
Names=list (the set (s) [r]. 'name' tolist ())) 
Print (names) 
Dict1=dict (zip (names, the list (random. Choice ([" doctor ", "workers", 'students']) for _ in names))) 
Print (dict1) 
S [' title ']=[' name '] s map (lambda x: dict1 [x]) 
Print (s) 

thanks brother!