I have a list of filenames in the format "filename PID00-00-00"
or just "PID00-00-00"
.
I want to extract part of the filename to create an ID
column.
I am currently using this code for the string extraction
names(df) <- stringr::str_extract(names(df), "(?<=PID)\\d ")
binded1 = rbindlist(df, idcol = "ID")%>%
as.data.frame(binded1)
This gives the ID
as the first set of digits after PID. e.g. filename PID1234-00-01
becomes ID 1234
.
I want to also extract the first hyphen and following digits. So from filename PID1234-00-01
I want 1234-00
.
What should my regex
be?
CodePudding user response:
try this:
stringr::str_extract(names(df),"(?<=PID)\\d{4}-\\d{2}")