Question about try and except using lists-CodePudding

So I had made this program thing in which it asks you to enter a random number, The number can only be from the list; [1, 2, 3, 4, 5, 6, 10] and nothing else.

I want to make if so if it is not from the list acceptables = [1, 2, 3, 4, 5, 6, 10] it will print "Illegal Number" and exit() program. But I cannot do it .

Here is what I tried:

invalids = ['7', '8', '9', '11']
acceptables = [1, 2, 3, 4, 5, 6, 10]
try :
    toss = int(input("Toss a number from 1 to 6 (10 included): "))
except ValueError:
    print("Invalid")

if toss != acceptables:
    print("Illegal Numbers!")
    time.sleep(2)
    exit()

But it doesn't seem to work, Can anyone help?

CodePudding user response：

This is because if the except block is executed, the toss variable has no value. Best choice would be to include the later code into the try block:

invalids = ['7', '8', '9', '11']
acceptables = [1, 2, 3, 4, 5, 6, 10]
try :
    toss = int(input("Toss a number from 1 to 6 (10 included): "))
    if toss not in acceptables:
        print("Illegal Numbers!")
        time.sleep(2)
        exit()
except ValueError:
    print("Invalid")

CodePudding user response：

Replace if toss != acceptables: by if toss not in acceptables: