There are two arrays:
$arrOne = [1, 3, 4];
$arrTwo = [2, 5,];
$newArr = [];
How to merge to get like this;
$newArr = [1, 2, 3, 4, 5];
Now displays through one, this option is not suitable.
foreach ($arrOne as $k => $v) {
$newArr[] = $v;
$newArr[] = $arrTwo[$k];
}
Here is another example. Tthe values can be different in the array.
$arrOne = [154, 32, 15];
$arrTwo = [682, 124,];
Again for this example it is necessary that the values from the second array always be at 2 and 5 positions in the new array:
$newArr = [154, 682, 32, 15, 124];
CodePudding user response:
You can use array_merge and sort functions to achieve this as following:
$newArr = array_merge($arrOne, $arrTwo); // it will be [1, 3, 4, 2, 5]
sort($newArr); // it will sort array [1, 2, 3, 4, 5]
You can use $newArr now which have sorted data
CodePudding user response:
You can use array_splice to merge the arrays in the intended way to the specific indices:
array_splice( $arrOne, 1, 0, $arrTwo[0]);
array_splice( $arrOne, 4, 0, $arrTwo[1]);
var_dump($arrOne);
Demo 1:
Using original data:
$arrOne = [1, 3, 4];
$arrTwo = [2, 5,];
Demo 2:
Using second set of data:
$arrOne = [154, 32, 15];
$arrTwo = [682, 124,];
CodePudding user response:
$arrOne = [1, 3, 4];
$arrTwo = [2, 5];
$newArr = [];
foreach($arrOne as $key => $one) {
switch($key) {
case 1:
$newArr[] = $arrTwo[0];
break;
case 4:
$newArr[] = $arrTwo[1];
break;
}
$newArr[] = $one;
}
if(count($newArr) < 5) {
$newArr[] = $arrTwo[1];
}
Here we are considering there will be always two elements in second array
CodePudding user response:
$arrayOne = [12,23,45,56,65,78,99];
$arrayTwo = [2,5];
$mergedArray = [];
foreach($arrayOne as $key => $value) {
$position = $key 1;
if ($position === 2) {
$mergedArray[] = $arrayTwo[0];
} else if ($position === 4) {
$mergedArray[] = $arrayTwo[1];
}
$mergedArray[] = $value;
}
CodePudding user response:
first of all you can merge the two arrays and then you can sort the merge array this will show like your output