How to find an element by a known src attribute using Selenium Python-CodePudding

I am trying to find an element by using Selenium with python, by a known value of src attribute. The element is the point picture on the left of the address of a location in Google Maps.

Namely the html for the element I'm trying to select:

<img alt="" jstcache="935" src="//www.gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp.png"  jsan="7.Liguzb,0.alt,8.src">

How can I select the given element by searching for it by using the link:

www.gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp.png

Thanks.

CodePudding user response：

To locate the element as the value of src attribute is know to you, you can use either of the following Locator Strategies:

Using css_selector:

element = driver.find_element(By.CSS_SELECTOR, "img.Liguzb[src*='gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp']")

Using xpath:

element = driver.find_element(By.XPATH, "//img[@class='Liguzb' and contains(@src, 'gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp')]")

To locate a visible element instead of presence_of_element_located() you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following locator strategies:

Using CSS_SELECTOR:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "img.Liguzb[src*='gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp']")))

Using XPATH:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//img[@class='Liguzb' and contains(@src, 'gstatic.com/images/icons/material/system_gm/1x/place_gm_blue_24dp')]")))

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC