In 8088 system, the memory address using byte addressing, RAM the address range is 00000 h ~ 3 FFFFH, if use 256 k * 1 21256 chip to pieces?
I know the capacity is 40000 h, but I don't calculate right, detailed process

CodePudding user response:

Memory is 40000 h 256 k bytes, with 256 k * 1 bit chip, that is, eight pieces of

CodePudding user response:

reference 1/f, play big shoot early nuclear response:

memory 40000 h is 256 k bytes, with 256 k * 1 bit chip, that is, eight pieces of

Ok, I see. Thanks

CodePudding user response:

reference 1/f, play big shoot early nuclear response:

memory 40000 h is 256 k bytes, with 256 k * 1 bit chip, that is, eight pieces of

I want to ask a question?
If use 16 k x 1 storage chip 64 KB memory, should be generated by the address line () decoding choose signal,

CodePudding user response:

A few days ago hasn't been in CSDN, 64 KB memory needs 16-bit address line, 16 kx1 chip on chip address is 14, so I need high line a15a14 two address decode produce piece selected signals (that is, each group of four groups of chip of eight 64 KB)