change dictionary key of dictionary by index-CodePudding

I have a dictionary dico that i created it with this code :

dico = {}
for index, row in data.iterrows():
    
    tup = (row['OsId'], row['BrowserId'])
    
   
    if tup not in dico:
        dico[tup] = []
    dico[tup].append(row['PageId'])
[print(f"{key} : {value}") for key, value in dico.items()]

here a sample of dico :

 combination : list of pages :

(99, 14) : [789615, 1158132, 789615, 789615, 1109643, 789615, 1184903]
(33, 16) : [955761, 955764, 955767, 955761, 955764, 955764, 1154705, 955761]
(12, 99) : [1068379, 1184903, 955764, 955761, 1184903, 955764]
(11, 99) : [1187774]

I am looking for a way to change the dico to replace the combination value by it's index in the list of combinations

For example i have the list of combination : (99, 14), (33, 16), (12, 99), (11, 99)

The expected result should be :

0 : [789615, 1158132, 789615, 789615, 1109643, 789615, 1184903]
1 : [955761, 955764, 955767, 955761, 955764, 955764, 1154705, 955761]
2 : [1068379, 1184903, 955764, 955761, 1184903, 955764]
3 : [1187774]

Any idea please to do it? thanks

CodePudding user response：

With a list of keys key_list = [(99, 14), (33, 16), (12, 99), (11, 99)]:

dict(enumerate(dico[k] for k in key_list))

CodePudding user response：

Is this what you want:

{i: value for i, value in enumerate(dico.values())}

CodePudding user response：

You cannot rename keys. You can iterate the list of keys (not directly) and insert the value of key old under another key and delete the old one:

keys = (99, 14), (33, 16), (12, 99), (11, 99)

d = {}
# iterates the LIST of keys, not dict.keys - that would not work
for idx, k in enumerate(keys,1):
    d[k] = 1111*idx

# before
print(d)

for idx,old in enumerate(keys):
    d[idx] = d[old]    # copy value
    del d[old]         # delete old key from dict

# after
print(d)

Output before:

{(99, 14): 1111, 
 (33, 16): 2222, 
 (12, 99): 3333, 
 (11, 99): 4444}

Output after:

{0: 1111, 
 1: 2222, 
 2: 3333, 
 3: 4444}

Or you create a fully new dict from it.

CodePudding user response：

This is a possible solution:

dico = dict(zip(range(len(dico)), dico.values()))

However, keep in mind that you're creating a new dictionary from scratch.

CodePudding user response：

The simplest solution is:

dico = dict(enumerate(dico.values()))

enumerate(dico.values()) gives you the equivalent of zip(range(len(dico)), dico.values()). Passing that sequence of tuples to dict() creates a new dictionary that uses the first element of each tuple as the key and the second element as the value.