I need a code which compares values inside a list and returns 1 or 0 in a separate list. My current version returns only None for some reasons. What am I doing wrong?
a=[1,2,3,4,5,9,1,1,2,3,4,5]
d=[]
for i in range(1,len(a)):
if a[i]>a[i-1]:
b=1
else:
b=0
f=d.append(b)
print(f)
CodePudding user response:
The reason it returns None
is because append()
method doesn't have a return value meaning it just updates the original value.
So, your code needs to be like this
a=[1,2,3,4,5,9,1,1,2,3,4,5]
d=[]
for i in range(1,len(a)):
if a[i]>a[i-1]:
b=1
else:
b=0
d.append(b)
print(d)
CodePudding user response:
some corrections and the script works properly
a=[1,2,3,4,5,9,1,1,2,3,4,5]
d=[]
for i in range(1,len(a)):
if a[i]>a[i-1]:
b=1
else:
b=0
d.append(b)
print(d)
CodePudding user response:
I simplify your code as follow:
d = []
f = d.append(1)
print(d)
print(f)
Maybe you can rewrite it as follow:
a=[1,2,3,4,5,9,1,1,2,3,4,5]
d=[]
for i in range(1,len(a)):
if a[i]>a[i-1]:
b=1
else:
b=0
d.append(b)
print(d)