Simulation figure as follows, single-chip microcomputer system of electronic clock design for 12 hours, display the information as follows: - HHMM empty SS. S empty, among them - on behalf of the morning or afternoon, not bright in the morning and afternoon light - HH on behalf of the hour, MM on behalf of the minutes, seconds, SS on behalf of the integer s representing decimal seconds, empty said does not display, I am to change, according to eight engineering simulation requirements need 10, now the program does not know how, ask bosses,

CodePudding user response:

 # include 
# include "intrins. H" 
# define uint unsigned int 
# define uchar unsigned char 

Sbit FMQ=P3 ^ 0;//?? U? Present?????? 

Char table []={xa4 xc0 0, 0 xf9, 0, 0, xb0 x99 0, 0 x92, 0 x82, 0 xf8, 0 x80, 0 x90, 0 XFF, 0 xc6, 0 xc7, 0 x88,};//12?????? Ey???? 1 u + a???? ? ° 0-9? Plus or minus 
//0 1 2 3 4 5 6 7 8 9 2??????? E? C L A 
Uchar val [8]=,0,0,0,0,0,11,12 {0};//ey???? 1 u?? E?? O3??? 

Uint count=0;//
Char shi=0, fen=0, miao=0;//e +??? Plus or minus? A? 
Char nzshi=0, nzfen=0, nzmiao=0;//??? Oe +,??? Plus or minus? A? 
Uchar wei=0 x01, duan=0;//?????? Ey???? 1 u?? Oi?????? E? Mu? Plus or minus? A? 

Led (void)//ey???? 1 ue ¨? Eo ˉ ey 
{
P0=0 XFF; 
The P2=wei; 
If ((duan==1) | | (duan==3))//? Aa? E?? OD? Ey mu? O? Mu? 
{
P0=(table [val [duan]] & amp; 0 x7f); 
} 
The else 
{
P0=table [val [duan]]. 
} 

Duan++; 
If (duan> 7) 
Duan=0; 
Wei=_crol_ (wei, 1); 
} 

Void time0init ()//? ¨ e +? Present 03? E?? ˉ 
{
TMOD=0 x01; 
TH0=(65536-2000)/256; 
TL0=(65536-2000) % 256; 
ET0=1; 
TR0=1; 
EA=1; 
} 

Uchar keytime=0;//?'? U 
Uint bjtime=0;//+ ¨? ˉ?? E + +? A? 
Bit SJBS=0;//?'? UA?????? E +?? X? I on mu? Plus or minus? A? 
Void time0 () interrupt 1//? ¨ e +? Present 0? D?? T.?? O ˉ ey 
{
TH0=(65536-2000)/256; 
TL0=(65536-2000) % 256; 
If (SJBS) 
{
count++; 
} 
Bjtime++; 
Keytime++; 
Leds ();//2 mse ¨? Eo? '? Ey???? 1 u?? E? 
} 


Uchar key ()//?'? Ue ¨? E3iDo 
{
The static uchar KZT=0; 
Uchar sb=25; 
The switch (KZT) 
{
Case 0: 
P1=0 XFF; 
If (P1!=0 XFF) 
{
KZT=1; 
The return of 25; 
} 
break; 
Case 1: 
P1=0 XFF; 
If (P1!=0 XFF) 
{
The switch (P1) 
{
Case 0 xfe: 
Sb=1; 
break; 
Case 0 XFD: 
Sb=2; 
break; 
Case 0 XFB: 
Sb=3; 
break; 
Case 0 xf7: 
Sb=4; 
break; 
Case 0 xef: 
Sb=5; 
break; 
Case 0 XDF: 
Sb=6; 
break; 
Case 0 XBF: 
Sb=7; 
break; 
Case 0 x7f: 
Sb=8; 
break; 
} 
KZT=2; 
Return sb. 
} 
The else 
{
KZT=0; 
The return of 25; 
} 
break; 

Case 2: 
P1=0 XFF; 
If (P1==0 XFF) 
{
KZT=0; 
The return of 25; 
} 
break; 
} 
The return of 25; 
} 


Void sj ()//e +??????? E +??? UD? 
{
If (count> 499) 
{
Count=0; 
Miao++; 
If (miao> 59) 
{
Miao=0; 
Fen++; 
If (fen> 59) 
{
Fen=0; 
Shi++; 
If (shi> 23) 
{
Shi=0; 
} 
} 
} 

} 

} 



Void main () 
{
Uchar keycode=25, zt=1; 
Bit BJBS=0; 
FMQ=1; 
Time0init ();//3? E?? ˉ? ¨ e +? Present 0 
While (1) 
{
If (keytime> 9)//20 ms e ¨? Eo? '? ° '? U 
{
Keytime=0; 
Keycode=key (); 
} 

If (((fen==0) & amp; & (miao==0)) | | ((shi==nzshi) & amp; & (fen==nzfen) & amp; & (miao==nzmiao))) 
{//? D?????? Mu? ? D?? E? Who? Mu?????? Oe +?? 
BJBS=1; 
FMQ=0; 
Bjtime=0; 
} 




If (BJBS)//+ ¨? ˉ '| ai 
{
If (bjtime> 30000) 
{
FMQ=1; 
BJBS=0; 
} 
If ((keycode> 1) & amp; & (keycode<5))//?? Oa? U? U? De - mu present? U? Ii on? 1? U? D 
{
BJBS=0; 
FMQ=1; 
} 
} 



The switch (zt) 
{
Case 1://e +? O?? E? 

Val [0]=shi/10;//?? E? Ey? Y? UD? 
Val [1]=shi % 10; 

Val [2]=fen/10; 
Val [3]=10 fen %; 

Val [4]=miao/10; 
Val [5]=miao % 10; 

Val [6]=11; 
Val [7]=12; 

If (keycode==1)//A to e +?????? DDo?? Yi on 
{
SJBS=! SJBS; 
Keycode=25; 
} 
Sj (); 

If (keycode==2)//B??????? O1 
{
Miao++; 
If (miao> 59) 
{
Miao=0; 
} 
Keycode=25; 
} 

If (keycode==3)//c.? ? O1 
{
Fen++; 
If (fen> 59) 
{
Fen=0; 
} 
Keycode=25; 
} 

If (keycode==4)//D e +? O1 
{
Shi++; 
If (shi> 23) 
{
Shi=0; 
} 
Keycode=25; 
} 

If (keycode==5)//E?? E?????? Oee?? X 'I? 
{
Zt=2; 
Keycode=25; 
} 

break; 


Case 2://??????? O?? E? O? Mu present? U 

Sj ();//e +??? UD? 
Val [0]=nzshi/10;//?? E? Ey? Y? UD? 
Val [1]=nzshi % 10; 

Val [2]=nzfen/10; 
Val [3]=nzfen % 10; 

Val [4]=nzmiao/10; 
Val [5]=nzmiao % 10; 

Val [6]=13; 
Val [7]=12; 

If (keycode==2)//B??????? O??? O1 
{
Nzmiao++; 
If (nzmiao> 59) 
{
Nzmiao=0; 
} 
Keycode=25; 
} 

If (keycode==3)//C??????? O.?? O1 
{
Nzfen++; 
If (nzfen> nullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnull