Is there a way to use the name of an object to a list instead of the value of that object?-CodePudding

The best way to demonstrate is through a basic code example:

aaa = 0
bbb = 0

objects_list = [aaa,bbb,aaa,bbb]

for obj in objects_list:
    obj  = 1

print(aaa)
print(bbb)

I understand that this way when creating the loop, the list is read like this:

objects_list = [0,0,0,0]

The print Terminal is:

0
0

The expected output in the terminal prints would be:

2
2

I'd like to recreate this here but in a loop:

aaa  = 1
bbb  = 1
aaa  = 1
bbb  = 1

Is there any way to create a list with object name instead of their values?

CodePudding user response：

You can't do that as integers are immutable, but there is a way around it:

objects_list = ["aaa", "bbb", "aaa", "bbb"]   # Note that they are strings

for obj in objects_list:
    locals()[obj]  = 1

Note that this type of programming is discouraged as it will confuse future maintainers and lead to subtle and hard to find bugs.

CodePudding user response：

Python's int is immutable. What you are asking is saving a "pointer" to the list. This is impossible for a integer, but needs an object. Here is an example how objects work:

class ValueWrapper(object):
    def __init__(self, value):
        self.value = value

    def __iadd__(self, x):
        self.value  = x

    def __str__(self):
        return str(self.value)

aaa = ValueWrapper(0)
bbb = ValueWrapper(0)

objects_list = [aaa,bbb,aaa,bbb]

for obj in objects_list:
    obj  = 1

print(aaa)
print(bbb)

Above codes give results

2
2