n= int(input())

a= list(range(1,"x",n 1)
print(a)

b=1:
    for b in a
        if num % 2 != 0:
           b= b*num
print(b)

This is for my into to python class and this is the question for context.

"Taking an integer value n from the user with input(). Your program will calculate the product of all odd numbers from 1 through the given n. For example: the user gave n=20. You python code will calculate the following value: 1 x 3 x 5 x 7 x 9 x 11 x 13 x 15 x 17 x 19 Your program will print out 654729075.0 back to the user. Please calculate the value for n=23 using your program?"

When I run my code, I keep getting an error saying perhaps I forgot a comma. Where would this be an issue within the code? The r in range keeps getting highlighted.

CodePudding user response：

Noticed a few issues here. First, you don’t need list() in your definition of a. You also don’t need a var named a at all.

Also, the syntax for range is range(start, stop, step). You want to start at 1, stop at n 1 (because range is exclusive), and move forward 2 each time. Therefore, it’s range(1, n 1, 2). The code will look like this:

n= int(input())

b=1
for num in range(1, n 1, 2):
    b *= num

print(b)

CodePudding user response：

try this: You are adding unnecessary "x" in code range should (start, end, [Step])

n= int(input())
a= list( range(1,n 1) )
print(a)
ans=1
for i in range(len(a)):
    if a[i] % 2 != 0: 
        ans*=a[i]
    else:
        continue
print(float(ans)

Read: Try to go through built in functions https://docs.python.org/3/library/functions.html

Range- https://docs.python.org/3/library/functions.html#func-range

List - https://docs.python.org/3/library/functions.html#func-list

CodePudding user response：

The code has several flaws. The expert comments are already indicating that. here is one possible version of executable code that can do what you want.

n= int(input())

a=list(range(1,n 1,2))
print(a)
b = 1
for num in a:
    b *= num
print(b)