An equation:
10 x + y=25 1475
Under the condition of x and y are integer, want to find out the x, y all the possible values,,,

How to write the written in Python, code?? Thank you very much!!!!!

CodePudding user response:

Integer x,
When x is equal to 15, greater than 1475
So, exhaustive all 1 & lt;=x & lt;
=15 of the integerJudgment is an integer, y so, added to the dictionary

CodePudding user response:

 
X_times=# 10 x n multiple 
Y_times=25 # y n ratio 
Xy_sum=1475 
X_range=xy_sum//x_times + 1 
Y_range=xy_sum//y_times + 1 

Serial_num=0 
For the x in the range (0, x_range) : 
For y in range (0, y_range) : 
If x_times * x + y_times * y==xy_sum: 
Serial_num +=1 
Print (" serial number={} : when x={}, y={}, meet the conditions of {} {} x + y=1475 ". The format (serial_num, x, y, x_times, y_times)) 

CodePudding user response:

Print statements to fine-tune the ha:
So x_times and y_times and xy_sum value you can modify!

 
X_times=# 10 x n multiple 
Y_times=25 # y n ratio 
Xy_sum=1475 
X_range=xy_sum//x_times + 1 
Y_range=xy_sum//y_times + 1 

Serial_num=0 
For the x in the range (0, x_range) : 
For y in range (0, y_range) : 
If x_times * x + y_times * y==xy_sum: 
Serial_num +=1 
Print (" serial number={} : when x={}, y={}, meet the conditions of x + y={} {} {} ". The format (serial_num, x, y, x_times y_times, xy_sum)) 

CodePudding user response:

Solving mathematics problems in mathematical way, this should eliminate the situation of negative integer about share, 2 x + 5=295, y x and y as an integer, and zero integer, analysis of x is 0, y=59 at this time, but not for 0, y and y must have for odd number, the minimum y is 1, so the result is x={0, 5, 10,... 145}, corresponding values for {57, 59, 55 y... 1},

CodePudding user response:

Excuse me,

X, y is a positive integer or an integer?

Integer solutions of words should be infinitely many

If it is a positive integer code written 3 floor is very good, the equivalent of y=x + 1475/25-10/25, for the first quadrant positive integer solutions

CodePudding user response:

10 x + y=25 1475

As the positive integer, X from 0 to 148
Y from 0 to 59

Traversal solution can

 
For x in the range (148 + 1) : 
For y in range (59 + 1) : 
If (10 * 25 * x + y)==1475: 
Print (x, y) 

CodePudding user response:

0 59
5 57
10 55
15 53
20 51
25 49
30 47
35 to 45
40 43
45 41
50 39
55 37
60 35
33 65
31 70
29 75
27 80
85 25
23 90
21 95
100 19
17 105
15 110
13 115
11 120
125
130 7
135
140
145 1

CodePudding user response:

If not consider negative integer x and y are & gt;=0, when x=0, 1475/25=59, when y=0, 1475/10=147.5 the integer is 148, so the code is as follows:

 
For x in the range (148 + 1) : 
For y in range (59 + 1) : 
If (10 * 25 * x + y)==1475: 
Print (x, y)