I need to regroup consecutive rows with same values for a list of columns. Thanks to this I've found how to do it for one column, but I can't make it work for more than one.
My question is quite close from this one but I can't make it work as I'd like either.
Here is a working snippet where I need the columns user
, group
, value1
and value2
to be identical to regroup the rows:
#! /bin/python3
import pandas as pd
data = [{"user":"paul","group":"accounting","value1":"foo","value2":3,"value3":"random123"},{"user":"paul","group":"accounting","value1":"foo","value2":3,"value3":"random456"},{"user":"paul","group":"accounting","value1":"foo","value2":3,"value3":"random789"},{"user":"paul","group":"accounting","value1":"foo","value2":5,"value3":"random789"},{"user":"paul","group":"accounting","value1":"foo","value2":5,"value3":"random789"},{"user":"paul","group":"accounting","value1":"foo","value2":5,"value3":"random158"},{"user":"jack","group":"administration","value1":"foo","value2":5,"value3":"random487"},{"user":"jack","group":"administration","value1":"foo","value2":5,"value3":"random435"},{"user":"jack","group":"administration","value1":"bar","value2":3,"value3":"random483"},{"user":"jack","group":"administration","value1":"foo","value2":3,"value3":"random431"},{"user":"jack","group":"administration","value1":"foo","value2":3,"value3":"random478"},{"user":"paul","group":"accounting","value1":"foo","value2":5,"value3":"random759"},{"user":"jack","group":"administration","value1":"bar","value2":3,"value3":"random431"},{"user":"jack","group":"administration","value1":"foo","value2":3,"value3":"random478"}]
df = pd.DataFrame(data)
print(df)
print("----")
grouped = df.groupby(((df['value2'].shift() != df['value2'])).cumsum())
for k, v in grouped:
print(f'[group {k}]')
print(v)
It outputs this:
[group 1]
user group value1 value2 value3
0 paul accounting foo 3 random123
1 paul accounting foo 3 random456
2 paul accounting foo 3 random789
[group 2]
user group value1 value2 value3
3 paul accounting foo 5 random789
4 paul accounting foo 5 random789
5 paul accounting foo 5 random158
6 jack administration foo 5 random487
7 jack administration foo 5 random435
[group 3]
user group value1 value2 value3
8 jack administration bar 3 random483
9 jack administration foo 3 random431
10 jack administration foo 3 random478
[group 4]
user group value1 value2 value3
11 paul accounting foo 5 random759
[group 5]
user group value1 value2 value3
12 jack administration bar 3 random431
13 jack administration foo 3 random478
But I need this:
[group 1]
user group value1 value2 value3
0 paul accounting foo 3 random123
1 paul accounting foo 3 random456
2 paul accounting foo 3 random789
[group 2]
user group value1 value2 value3
3 paul accounting foo 5 random789
4 paul accounting foo 5 random789
5 paul accounting foo 5 random158
[group 3]
user group value1 value2 value3
6 jack administration foo 5 random487
7 jack administration foo 5 random435
[group 4]
user group value1 value2 value3
8 jack administration bar 3 random483
[group 5]
user group value1 value2 value3
9 jack administration foo 3 random431
10 jack administration foo 3 random478
[group 6]
user group value1 value2 value3
11 paul accounting foo 5 random759
[group 7]
user group value1 value2 value3
12 jack administration bar 3 random431
[group 8]
user group value1 value2 value3
13 jack administration foo 3 random478
I tried multiple columns in the groupby but to no avail:
grouped = df.groupby(((df[['user', 'value2']].shift() != df[['user', 'value2']])).cumsum())
#returns
ValueError: Grouper for '<class 'pandas.core.frame.DataFrame'>' not 1-dimensional
CodePudding user response:
Create consecutive groups by compare columns from list with DataFrame.any
and then add cumulative sum:
cols = ['user','group','value1','value2']
grouped = df.groupby(((df[cols].shift() != df[cols]).any(axis=1)).cumsum())
for k, v in grouped:
print(f'[group {k}]')
print(v)
[group 1]
user group value1 value2 value3
0 paul accounting foo 3 random123
1 paul accounting foo 3 random456
2 paul accounting foo 3 random789
[group 2]
user group value1 value2 value3
3 paul accounting foo 5 random789
4 paul accounting foo 5 random789
5 paul accounting foo 5 random158
[group 3]
user group value1 value2 value3
6 jack administration foo 5 random487
7 jack administration foo 5 random435
[group 4]
user group value1 value2 value3
8 jack administration bar 3 random483
[group 5]
user group value1 value2 value3
9 jack administration foo 3 random431
10 jack administration foo 3 random478
[group 6]
user group value1 value2 value3
11 paul accounting foo 5 random759
[group 7]
user group value1 value2 value3
12 jack administration bar 3 random431
[group 8]
user group value1 value2 value3
13 jack administration foo 3 random478