A: 10.0.0.0 - those that 10.0.0.0/8
B: along - 172.31.255.255 namely along/12
C: 192.168.0.0-192.168.255.255 namely 192.168.0.0/16
Don't understand the address range can be written as diagonal/8,/12/16, have no prawn about solving process, thank you very much,
CodePudding user response:
This writing is called address together: slash in front of the part is called the network segment address, behind the forward slash represents mask digits, and through the mask to identify the IP network, IP range,Such as 10.0.0.0/8 said this is an 8 bit mask of the IP section, before eight is a fixed network, after 24 can change, change the range is fixed (10). 0.0.0 ~ (10 fixed) 255.255.255,
CodePudding user response:
The normal writing of mask is:255.255.255.0 this called dotted decimal to man's memory, calculation,
But the machine is the binary 1111111.11111111.11111111.00000000
Here is a total of 24 1 so 24 so writing/24
In the same way/8 11111111.0.0.0 255.0.0.0's
/9 - & gt; 11111111.1000000.00000000.00000000 - & gt; 255.128.0.0
CodePudding user response:
Written address range/8 means only eight such as network address 10.0.0.0/8 means that A class A address themselves to use from the 10.0.0.0 - behind those