Repeat character depending on position in array 1-CodePudding

I'm trying to get an output like this:

['h', 'ee', 'lll', 'llll', 'ooooo']

currently my out put is:

[ 'h', 'ee', 'lll', 'lll', 'ooooo' ]

The issue is the second occurrence of the "l" isn't being repeated one more time because I'm counting the index of the letter then adding 1 and it is only counting the first occurrence of the "l". This is the code I have so far, any help would be great.

function mumble(string) {
  string.toLowerCase();
  let arrayPush = [];
  let array = string.split("");
  let count = 0;
  let char = [];
  array.map((letter) => {
    count = array.indexOf(letter);

    arrayPush.push(letter.repeat(count   1));
  });

  return arrayPush;
}

console.log(mumble("hello"));

CodePudding user response：

Don't use indexOf, use the second parameter in the .map callback to determine the index (and from that, the number of times to repeat the string).

function mumble(string) {
  string.toLowerCase();
  let arrayPush = [];
  let array = string.split("");
  let count = 0;
  let char = [];
  array.map((letter, i) => {
    arrayPush.push(letter.repeat(i   1));
  });

  return arrayPush;
}

console.log(mumble("hello"));

CodePudding user response：

Instead of applying .map to an array split from the string, you can simply loop through the string, accessing each character using the .charAt() string method, and pushing it's .repeat() product to the result array.

Working snippet:

console.log(mumble('hELlo'));

function mumble(string) {
const result = [];

for(let i=0; i<string.length; i  ) {
    result.push(string.toLowerCase().charAt(i).repeat(i 1));
}

return result;
} // end function mumble;