python remove 0 from dictionary value list-CodePudding

 {'INF_Test': ['mi-0e6d869b68d49c2c4', 0, 0], 'INF_Test2': [0, 'mi-0a5d9089f493ae12a', 'mi-04506ea0d2810d3d5']}

need to be like output

 {'INF_Test': ['mi-0e6d869b68d49c2c4'], 'INF_Test2': ['mi-0a5d9089f493ae12a', 'mi-04506ea0d2810d3d5']}

CodePudding user response：

You can use a list comprehension and a dictionary comprehension:

{key: [item for item in value if item != 0] for key, value in data.items()}

This outputs:

{
 'INF_Test': ['mi-0e6d869b68d49c2c4'],
 'INF_Test2': ['mi-0a5d9089f493ae12a', 'mi-04506ea0d2810d3d5']
}

CodePudding user response：

There are many ways to do this. Here's an opportunity to use filter():

d = {'INF_Test': ['mi-0e6d869b68d49c2c4', 0, 0], 'INF_Test2': [0, 'mi-0a5d9089f493ae12a', 'mi-04506ea0d2810d3d5']}

e = {k : list(filter((0).__ne__, v)) for k, v in d.items()}

CodePudding user response：

aaa = {'INF_Test': ['mi-0e6d869b68d49c2c4', 0, 0], 'INF_Test2': [0, 'mi-0a5d9089f493ae12a', 'mi-04506ea0d2810d3d5']}
for key in aaa.keys():
    aaa[key] = list(filter(lambda num: num != 0, aaa[key]))

print(aaa)

Output

{'INF_Test': ['mi-0e6d869b68d49c2c4'], 'INF_Test2': ['mi-0a5d9089f493ae12a', 'mi-04506ea0d2810d3d5']}