CodePudding user response:

 import itertools as it 

A1=[[3, 'European'], [2, 'America']] 
A2=[[4, 'Asia'], [2, 'Oceania]] 
A3=[[1, 'Asia'], [5, 'African']] 
A4=[[4, 'African'], [3, 'Oceania]] 
A5=[[2, 'European'], [5, 'America']] 

D=[a1, a2, a3, a4, a5] 
G=[list (zip (* _)) for _ in it. The product (a1, a2, a3, a4, a5)] 
R=the filter (lambda x: len (set) (x [0])==5 and len (set) (x [1])==5, g) 
Print (sorted (list (zip (* list (r) [0])))) 


D={' monkey '5,' cat ': 5,' dog ', 5, 'deer: 5,' rabbit ': 5} 
X=[[' monkey ', 'cat'], [' deer 'and' dog '], [' rabbit ', 'monkey'], [' dog ', 'rabbit']] * 2 
For _ in x: 
A=d.g et (_ [0], 0) 
B=d.g et (_ [1], 0) 
A=b - 1 
D.u pdate ({_ [0] : a}) 

Print (sorted (d.i tems (), key=lambda x: x [1]))