But accidentally R2 in this picture into a 1 m, put into 5 v voltage, the results when connected to a multimeter current file (mA), resistor R5 burn out
Presumably due to transistor in saturated conductivity state in R5 current is too large, but even if I put the state in the simulation to restore the situation of the resistance before burning, transistor Q1 is far from saturated zone
Sincerely ask, why R5 will burn,
CodePudding user response:
From the circuit parameters are calculated to 500 ohms 24 v current 48 ma, however, then calculate 50 ohm power of 2.4 watts, burning may use the resistance of the power may be small.CodePudding user response:
Simulation is, after all, the simulation and hardware or discriminating, not to believe the simulation.CodePudding user response:
Due to circuit compound gain very high after a triode, occasional self-excited led to the output full convergence,Need to increase the compensation circuit, in order to reduce the response speed, the principle of self-excited conditions,
Method 2:20 years ago, we often do this)
1. R4 in parallel in a 104-105
2. Add compensation capacitance between the triode BC (47-1000 - p)
Concrete numerical value according to the circuit response speed requirements,
Circuit and other system coupling circuit, had increased vibration instead, remove the coupling didn't,