I am trying to open my Unity application through command prompt. I would like to pass on width and height so it could open in that resolution. I am using Screen.SetResolution() but I don't know how to pass the arguments:
// Use this for initialization
void Awake()
{
Screen.SetResolution(h, w, false);
}
Command line - UnityApp.exe -screen-width 800 -screen-height 570 -screen-fullscreen 0
CodePudding user response:
You should be able to grab the applications command line arguments with the following using System.Environment.CommandLine & System.Environment.CommandLineArgs:
string[] args = System.Environment.GetCommandLineArgs();
int widthInput;
int heightInput;
for (int i = 0; i < args.Length; i )
{
Debug.Log("ARG " i ": " args[i]);
if (args[i] == "-screen-width")
{
int.TryParse(args[i 1], out widthInput);
} else if(args[i] == "-screen-height") {
int.TryParse(args[i 1], out heightInput);
}
}
if(heightInput != null && widthInput!=null)
Screen.SetResolution(heightInput , widthInput, false);
Here is a link of the source code readjusted to suit your needs: https://answers.unity.com/questions/138715/read-command-line-arguments.html
Hope this helps!