Compare string values from two different lists at once and print the wrong value at the end-CodePudding

I have two lists which I extracted from two different paths and created a list:

list1 = ["123", "", "6/6/2020", "testing"]
list2 = ["6/6/2020", "testing", "hello"]

I need to compare if list1[2] == list2[0] and list1[3] == list2[1] and list1[1] == list2[2]
At the end I want to print "value of list1[1] does not match". How to write a python code? Please help with this.

Thanks in advance.

CodePudding user response：

Your question is quite unclear and I am missing your own code for this. Would you need to compare all items in list1 with all items in list2? In that case it sounds like the job for a double for loop.

for each i in list1:
    for each j in list2:
        if list1[i] == list2[j]:
            do something

I will not write the code for you since this is such basic code.

CodePudding user response：

As I understand the question you want to output which value of list1 doesn't match. You're a bit unclear in the question about that.

You have

list1 = ["123", "", "6/6/2020", "testing"]
list2 = ["6/6/2020", "testing", "hello"]

Now transform list2 so that it matches the structure of list1.

list2 = [list1[0]]   [list2[2]]   list2[:2]

This will give you ['123', 'hello', '6/6/2020', 'testing'] for list2. Now comparing and printing a message for the non-match is easy:

for i, values in enumerate(zip(list1, list2)):
    if values[0] != values[1]:
        print(f'list[{i}] does not match')

Result: list[1] does not match.