pandas iterate over column values at once and generate range-CodePudding

I have a pandas dataframe like as below

df1 = pd.DataFrame({'biz': [18, 23], 'seg': [30, 34], 'PID': [40, 52]})

I would like to do the below

a) pass all the values from each column at once to for loop

For ex:

I am trying the below

cols = ['biz','seg','PID']
for col in cols:
  for i, j in df1.col.values:
      print("D"   str(i)   ":"   "F"   str(j))
      print("Q"   str(i)   ":"   "S"   str(j))
      print("AB"   str(i)   ":"   "AD"   str(j))

but this doesn;t work and I get an error

TypeError: cannot unpack non-iterable numpy.int64 object

I expect my output to be like as below

D18:F23
Q18:S23
AB18:AD23
D30:F34
Q30:S34
AB30:AD34
D40:F52
Q40:S52
AB40:AD52

CodePudding user response：

The mistake is in the innermost forloop.

You are requesting an iterator over a 1-dimensional array of values, this iterator yields scalar values and hence they can not be unpacked.

If your dataframe only has 2 items per column, then this should suffice

cols = ['biz','seg','PID']
for col in cols:
   i, j = getattr(df1, col).values
   print("D"   str(i)   ":"   "F"   str(j))
   print("Q"   str(i)   ":"   "S"   str(j))
   print("AB"   str(i)   ":"   "AD"   str(j))

CodePudding user response：

for i in range(len(df1)):
    print('D'   str(df1.iloc[i,0])   ':'   'F'   str(df1.iloc[i 1,0]))
    print('Q'   str(df1.iloc[i,0])   ':'   'S'   str(df1.iloc[i 1,0]))
    print('AB'   str(df1.iloc[i,0])   ':'   'AD'   str(df1.iloc[i 1,0]))
    print('D'   str(df1.iloc[i,1])   ':'   'F'   str(df1.iloc[i 1,1]))
    print('Q'   str(df1.iloc[i,1])   ':'   'S'   str(df1.iloc[i 1,1]))
    print('AB'   str(df1.iloc[i,1])   ':'   'AD'   str(df1.iloc[i 1,1]))
    print('D'   str(df1.iloc[i,2])   ':'   'F'   str(df1.iloc[i 1,2]))
    print('Q'   str(df1.iloc[i,2])   ':'   'S'   str(df1.iloc[i 1,2]))
    print('AB'   str(df1.iloc[i,2])   ':'   'AD'   str(df1.iloc[i 1,2]))