How to get the URL from this string in bash?-CodePudding

I have a bunch of strings formatted like this:

myFolder/myUrl.com.zip

I need a bash script that takes this input, and returns

myUrl.com

How can I do this?

CodePudding user response：

If the URLs in question are just hostnames like the example provided, and all of the 'encapsulated' URLs have a single file extension at the end, then Bash's remove longest/ shortest matching substrings at beginning and end of string expansions should help:

${VAR%pattern} - remove shortest matching string from beginning
${VAR%%pattern} - remove longest matching string from beginning
${VAR#pattern} - remove shortest matching string from end
${VAR##pattern} - remove longest matching string from end

Assuming an input variable of URI (which could be read from a file or input stream), the following would remove any directories from the beginning, and one file extension from the end (result is returned back in URI):

# Remove chars from the beginning up to and including the last forward slash (folders)
URI="${URI##*/}"

# Remove chars from the end back to and including the closest dot to the end (file ext.)
URI="${URI%.*}"

See https://tldp.org/LDP/abs/html/parameter-substitution.html for more detail

CodePudding user response：

If the strings are located in files, then use

grep -Po "[^/] \.com" file.txt

CodePudding user response：

$ basename -s .zip myFolder/myUrl.com.zip
myUrl.com