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Cipher algorithm (master), please consult

Time:10-04

A group of ciphertext, all the length of the cipher is 29, 23 and 24 of them are two equal sign, behind five is ABABA format data
Similar
HG2JPctCuiMhh8RNKctEUQ==48484
Ecek1mK9gqi1456ILwmLmQ==/3/3/
HcFZ/P + ayrmL3gUGNF1MNA==7; 7. 7
Adoption of the 22 is in front of the base64 encoding decoding, such as the format of the third password before 22 decoding is
H 07 00000111
C 28 00011100
05 F 00000101
Z 25 00011001
/63 00111111
15 00001111 P
+ 62 00111110
A 26 00011010
Y 50 00110010
43 00101011 r
M 38 00100110
L 11 00001011
3 55 00110111
G 32 00100000
U 00010100
G 06 00000110
N 13 00001101
05 F 00000101
53, 00110101 1
M 12 00001100
N 13 00001101
A 00 00000000
A total of 22, the former for the beginning of the 21 00, 00 also remove the last one in addition to remove the beginning at the end of 0000 to get this, the Bin convert Hex:
00011101 1 d
11000001 C1
59 01011001
FC 11111100
11111111 FF
10011010 9 a
CA 11001010
10111001 B9
10001011 8 b
DE 11011110
00000101-05
06 00000110
00110100 34
01011101 5 d
01001100 4 c
00110100 34

But 1 dc159fcff9acab98bde0506345d4c34
Use md5 cannot explain, is at the back of the five may be check code, o master

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