Insert values of list of lists in a dictionary declared with keys-CodePudding

I have this list of lists:

x = [['x1', 'x2', 'x3', 'x4', 'x5', 'x6', 'x7', 'x8', 'x9', 'x10', 'x11'], 
    ['x1', 'x2', 'x3', 'x4', 'x5', 'x6', 'x7', 'x8', 'x9', 'x10', 'x11'], 
    ['x1', 'x2', 'x3', 'x4', 'x5', 'x6', 'x7', 'x8', 'x9', 'x10', 'x11']]

And I have a declared dictionary like:

d = {"x": None, "y": None, "z": None, "t": None, 
"a": None, "s": None, "m": None, "n": None, 
"u": None, "v": None, "b": None}

What I want to get is a list or dictionry such as:

result = [{"x": x1,
"y": x2,
"z": x3,
"t": x4,
"a": x5,
"s": x6,
"m": x7,
"n": x8,
"u": x9,
"v": x10,
"b": x11}, {"x": x1,
"y": x2,
"z": x3,
"t": x4,
"a": x5,
"s": x6,
"m": x7,
"n": x8,
"u": x9,
"v": x10,
"b": x11}...]

And so on. One dictionary inside the list per each element inside x (list of lists).

Solutions in python3 are correct,however in python2 would be even better.

CodePudding user response：

Try:

result = [dict(zip(d, subl)) for subl in x]
print(result)

Prints:

[
    {
        "x": "x1",
        "y": "x2",
        "z": "x3",
        "t": "x4",
        "a": "x5",
        "s": "x6",
        "m": "x7",
        "n": "x8",
        "u": "x9",
        "v": "x10",
        "b": "x11",
    },
...

The dict(zip(d, subl)) will iterate over keys of dictionary d and values of sublists of x at the same time and creates new dictionary (with keys from d and values from sublist). This works for Python 3.7 as the dictionary keeps insertion order.

CodePudding user response：

From Python 3.7, dictionary order is guaranteed to be insertion order. So my answer does only make sense if you're using Python >=3.7.

Here is how you can do it:

result = [dict(zip(d, lst)) for lst in x]