Parse Out Elements of a String in a List To Create DataFrame in Python-CodePudding

I'm brand new to Python so I hope this makes sense:

I've created a list from file names I've pulled using the os module.

The file names look like '### Name 00.00', so there are integers, words, and floats all mixed into single strings in my list. It looks like this:

files_list = ['### File1 00.00','### File2 00.00','### File3 00.00']

I really need it to look something like:

files_list = [['###','File1','00.00'],['###','File2','00.00'],['###','File3','00.00']]

That way I can create a dataframe with the columns "Invoice #", "Vendor" , "Amount".

However, all I've been able to figure is to create a nested list with each string, so:

files_list = [files[i:i 1] for i in range(0, len(files), 1)]

#which returns this format:
files_list = [[### File1 00.00],[### File2 00.00],[### File3 00.00]]

I'm sure there's a super simple solution, but I just don't know exactly how to ask the question in google.

TYIA

CodePudding user response：

import pandas as pd

labels = ["Invoice #", "Vendor", "Amount"]

files_list = ["### File1 00.00", "### File2 00.00", "### File3 00.00"]

pd.DataFrame.from_records(dict(zip(labels, x.split(" "))) for x in files_list)

result:

  Invoice # Vendor Amount
0       ###  File1  00.00
1       ###  File2  00.00
2       ###  File3  00.00

CodePudding user response：

You can use pd.Series.str.split:

pd.Series(files_list).str.split().tolist()

produces:

[['###', 'File1', '00.00'],
 ['###', 'File2', '00.00'],
 ['###', 'File3', '00.00']]