How would I check if an array in another array contains x?-CodePudding

I am coding chess and am wondering how I would check if an array in another array contains x. It would work something like this:

if(array contains array containing x)

CodePudding user response：

You can use flat() to monodimensionalize the array and includes() to check.

let x = [0, 1, 2, [3, 4]];

if(x.flat(Infinity).includes(3)) {
  console.log("yes");
}

EDIT: Using Infinity as a parameter, as said in the comments, for multi-level arrays.

CodePudding user response：

If I understood your question you can do something like this

const contains = (data, x) => data.some(d => d.includes(x))

const data1 = [
 [1],
 [2, 3, 4],
 [5]
]

console.log(contains(data1, 1), contains(data1,2), contains(data1, 7))

if you want a recursive approach you can do something like this

const contains = (data, x) => {
  if(typeof data !== 'object'){
    return data === x
  }
  
  return data.some(d => contains(d, x))
}

const data1 = [
  [
    [1]
  ],
  [2],
  [[3, [4]]]
]

console.log(contains(data1, 1), contains(data1, 2),contains(data1, 3),contains(data1, 5))