How to find Index of element from array when array contains number and Brackets in string format-CodePudding

I have an array var arr = ['(', '1', 'AND', '2', ')', 'OR', '(', '3', 'AND', '4', ')']

First I want to find if my array contains a element if have that element then replace it with another string.

I have tried following

arr.find(element=>{
  if(element == 1){
  var elementIndex = arr.indexOf(1);
  arr[elementIndex] = "Name = Test";
}
})

Here I'm searching for "1" in array. But always give me output as -1.

what I am doing wrong?

CodePudding user response：

You should use the map array function as so:

var arr = ['(', '1', 'AND', '2', ')', 'OR', '(', '3', 'AND', '4', ')'];

var newArray = arr.map(el => el === '1' ? 'new_value' : el);

will output:

[
    "(",
    "new_value",
    "AND",
    "2",
    ")",
    "OR",
    "(",
    "3",
    "AND",
    "4",
    ")"
]

CodePudding user response：

Similar to what trincot said, your if statement is incorrect. Your if statement is looking for the number 1. Your array has the string "1".

CodePudding user response：

var arr = ['(', '1', 'AND', '2', ')', 'OR', '(', '3', 'AND', '4', ')']
        arr.find(element => {
            if (element === '1') {
                var elementIndex = arr.indexOf(element);
                arr[elementIndex] = "Name = Test";
                console.log(elementIndex)
            }
        })

CodePudding user response：

var arr = ["(", "1", "AND", "2", ")", "OR", "(", "3", "AND", "4", ")"];

const idx = arr.findIndex((el) => el === "1");
if (idx > -1) {
  arr[idx] = "Name = Test";
}