As shown in figure, the upper limit is 1 million, the last time I estimate must measure 1 million, is a timeout
The code is as follows:

 f1=1 
F2=1 
List_1=[f1, f2] 

For I in range (2, int (input ())) : 
List_1 list_1 [0], [1]=list_1 list_1 [0] + [1], list_1 [0] 

Print (list_1 [0] % 10007) 

Baidu is no any code in python,,,
Dalao they teach me how to improve orz

CodePudding user response:

Blogger is not in accordance with the specification, can try to take more than sum again

CodePudding user response:

reference 1/f, stay hungry * reply:

bloggers write according to the specification, can try to take more than sum again

because I did not , I can't imagine how to implement doesn't count for remainder directly

CodePudding user response: