Python regex how to remove all zeo from beginning?-CodePudding

I have lot of string somethings like this "01568460144" ,"0005855048560"

I want to remove all zero from beginning. I tried this which only removing one zeo from beginning but I also have others string those have multiple zeo at the beginning.

re.sub(r'0','',number)

so my expected result will be for "0005855048560" this type of string "5855048560"

CodePudding user response：

If the goal is to remove all leading zeroes from a string, skip the regex, and just call .lstrip('0') on the string. The *strip family of functions are a little weird when the argument isn't a single character, but for the purposes of stripping leading/trailing copies of a single character, they're perfect:

>>> s = '000123'
>>> s = s.lstrip('0')
>>> s
'123'

CodePudding user response：

>>> v = '0001111110'
>>> 
>>> str(int(v))
'1111110'
>>> 
>>> str(int('0005855048560'))
'5855048560'