I have below code.
var
result := 'DECLARE''' #13#10 'DECLARE''''';
result := TRegEx.Replace(result, '\A\s*DECLARE''\s*', 'abc', [roIgnoreCase]);
ShowMessage(result);
When I run it, I got:
This result is expected. However, when I change the replacement string to an empty string, like this:
result := 'DECLARE''' #13#10 'DECLARE''''';
result := TRegEx.Replace(result, '\A\s*DECLARE''\s*', '', [roIgnoreCase]);
ShowMessage(result);
I got this result when run the program:
Why this happens? I only want to replace the first match, and that's why I use \A
to anchor the regex at the beginning of the string.
CodePudding user response:
The reason why you get the results you get is because TRegEx.Replace replaces all matches in an Input string with a Replacement string.
If you want to replace only the first match then you need to use overloaded version of TRegEx.Replace
that allows you to also pass the Count parameter with which you can control of how many occurrences gets replaced.
Since this overloaded version of TRegEx.Replace
is declared as regular function belonging to TRegEx
record and not as class function
you will first have to declare variable of TRegEx record and set Pattern and Options using TRegEx.Create and then call appropriate overloaded version of Replace
.
So your code should look like this:
var RegEx: TRegEx;
result := 'DECLARE''' #13#10 'DECLARE''''';
RegEx := TRegEx.Create('\A\s*DECLARE''\s*', [roIgnoreCase]);
Result := RegEx.Replace(Result,'abc',1);
ShowMessage(result);
result := 'DECLARE''' #13#10 'DECLARE''''';
RegEx := TRegEx.Create('\A\s*DECLARE''\s*', [roIgnoreCase]);
Result := RegEx.Replace(Result,'',1);
ShowMessage(result);
This then returns abcDECLARE''
for abc
replacement string and DECLARE''
for empty replacement string.