I have a batch file that is supposed to execute a powershell script and I also want pass a file path to the script out of the batch file. The file path should then be inserted at a certain point in the script.

$Berechtigung = Get-ACL -Path "C:\_TEST\TEST.txt"

do you have any ideas?

CodePudding user response：

• From a batch file (cmd.exe), you must call the Windows PowerShell CLI, powershell.exe, in order to execute a PowerShell script (.ps1), optionally with arguments, via the -File parameter.

• In your PowerShell script, you can refer to arguments passed by the caller:

  • either: purely positionally, via the automatic $args variable, where $args[0] contains the first argument, $args[1] the second, and so on.
  • or: via declared parameters, such as param([string] $Path) - see the relevant section of the conceptual about_Functions help topic.

Therefore:

Assuming your PowerShell script is named foo.ps1 and contains the following content:

# Content of foo.ps1

param([string] $Path)  # Declare a string parameter named -Path

$Berechtigung = Get-ACL -Path $Path

You can then call this script from your batch file as follows (this assumes that foo.ps1 is located in the current directory - adjust as needed):

@echo off

:: ...

powershell.exe -NoProfile -File .\foo.ps1 "C:\_TEST\TEST.txt"

Note that if you declare parameters (with param(...)) you can also pass your arguments as named ones, namely by placing the target parameter name before an argument:

:: Note the -Path before the file path.
:: Only works if you have declared this parameter via param(...)
powershell.exe -NoProfile -File .\foo.ps1 -Path "C:\_TEST\TEST.txt"