I have text and want to find the number of letters like 'a', 'i', and also the word 'it'. I've been able to find the number of letters 'a' and 'i', but for the word 'that' I can't find
let text = "Lorem ipsum dolor sit amet consectetur adipisicing elit. Culpa, perspiciatis? Reiciendis, facere nobis libero officiis labore sit, deserunt maiores perferendis tempore quas neque odit. Quasi culpa totam aspernatur deserunt nobis."
let words = ["a", "i", "it"]
result_a = [];
result_i = [];
result_it = [];
for (let i = 0; i < words.length; i ) {
for (let j = 0; j < text.length; j ) {
if (words[i] == text[j] && words[i] == words[0]) {
result_a.push(text[j]);
} else if (words[i] == text[j] && words[i] == words[1]) {
result_i.push(text[j])
} else if (words[i] == text[j] && words[i] == words[2]) {
result_it.push(text[j])
}
}
}
console.log(result_a.length) //13
console.log(result_i.length) //24
console.log(result_it.length) //0
The output I expect is the number of each word searched for, for example the number of 'a' in the text variable is 13
my code is too long, is there a more concise way? and how to find 'it'
CodePudding user response：
I would just use a replacement trick here:
var text = "Lorem ipsum dolor sit amet consectetur adipisicing elit. Culpa, perspiciatis? Reiciendis, facere nobis libero officiis labore sit, deserunt maiores perferendis tempore quas neque odit. Quasi culpa totam aspernatur deserunt nobis.";
var letters = ["a", "i"];
for (var i=0; i < letters.length; i) {
var num = text.length - text.replace(new RegExp(letters[i], "g"), "").length;
console.log("number of " letters[i] ": " num);
}If you want to search for it as a standalone word, then we need to search for \bit\b. But, this is very different from finding letters anywhere in the string.
CodePudding user response：
First Solution:
Counting occurrence of each searchElement, regardless of char or word, as a substring in text.
let text = "Lorem ipsum dolor sit amet consectetur adipisicing elit. Culpa, perspiciatis? Reiciendis, facere nobis libero officiis labore sit, deserunt maiores perferendis tempore quas neque odit. Quasi culpa totam aspernatur deserunt nobis."
let searchElement = ["a", "i", "it"]
var wordToCount = {};
searchElement.forEach( word => {
let searchText = new RegExp(word, 'g')
var matchCount = (text.match(searchText) || []).length;
wordToCount[word] = matchCount;
});
for (const [key, value] of Object.entries(wordToCount)) {
console.log(key, value);
}Second Solution:
In case the searchElemement is a character counting its occurrence. Otherwise, searching it as a word.
let text = "Lorem ipsum dolor sit amet it conseitctetur adipisicing elit. Culpa, perspiciatis? Reiciendis, facere nobis libero officiis labore sit, deserunt it maiores perferendis tempore quas neque odit. Quasi culpa totam aspernatur deserunt nobis."
let searchElems = ["a", "i", "it"]
// handles character occurance count
var wordToCount = {};
let searchChars = searchElems.filter(word => word.length === 1)
searchChars.forEach( char => {
let searchText = new RegExp(char, 'g')
var matchCount = (text.match(searchText) || []).length;
wordToCount[char] = matchCount;
});
// handles word occurance count
let textTokens = text.split(" ");
let searchWords = searchElems.filter(word => word.length > 1)
let searchWordsSet = new Set(searchWords)
textTokens.forEach( word => {
if (searchWordsSet.has(word))
wordToCount[word] =
wordToCount[word] != undefined ? wordToCount[word] 1: 1
})
for (const [key, value] of Object.entries(wordToCount)) {
console.log(key, value);
}CodePudding user response：
Just use RegExp for finding all match and get length
let text = "Lorem ipsum dolor sit amet consectetur adipisicing elit. Culpa, perspiciatis? Reiciendis, facere nobis libero officiis labore sit, deserunt maiores perferendis tempore quas neque odit. Quasi culpa totam aspernatur deserunt nobis."
let words = ["a", "i", "it"]
for (var i=0; i < words.length; i ) {
regexWord = new RegExp( words[i], 'g');
var count = ((text || '').match(regexWord) || []).length
console.log("number of " words[i] ": " count);
} CodePudding user response：
You can use an object to keep track of the count. Not the most efficient solution but readable and should be fine if the inputs are not large.
let text = "Lorem ipsum dolor sit amet consectetur adipisicing elit. Culpa, perspiciatis? Reiciendis, facere nobis libero officiis labore sit, deserunt maiores perferendis tempore quas neque odit. Quasi culpa totam aspernatur deserunt nobis."
let words = ['a', 'i', 'it'];
let wordCount = {
'a': 0,
'i': 0,
'it': 0
};
for (let i = 0; i < text.length; i ) {
for (const word of words) {
if (text.substring(i).startsWith(word)) {
wordCount[word] ;
}
}
}
CodePudding user response：
When you use for cycle on text string text[j] is one character in that string and when you compare it to words[i] it matches because in this case
let words = ["a", "i", "it"]
they are one characters, but if add word there, for example the word 'that' it will try to compare word 'that' to every single character from text string separatly
you can change it like this
function getCount(arr, val) {
var indexes = [], i;
for(i = 0; i < arr.length; i )
if (arr[i] === val)
indexes.push(i);
return indexes.length;
}
CodePudding user response：
let text = "Lorem ipsum dolor sit amet consectetur adipisicing elit. Culpa, perspiciatis? Reiciendis, facere nobis libero officiis labore sit, deserunt maiores perferendis tempore quas neque odit. Quasi culpa totam aspernatur deserunt nobis."
let words = ["a", "i", "it"]
result_a = 0;
result_i = 0;
result_it = 0;
for (let i = 0; i < text.length; i ) {
if (text[i] == words[0])
result_a ;
if(text[i] == words[1])
result_i ;
if (text[i] == words[2][0] && text[i 1] == words[2][1])
result_it ;
}
console.log(result_a) //13
console.log(result_i) //24
console.log(result_it) //4