How to Read in a String With Spaces into a Linked List?-CodePudding

So essentially I am reading data into this linked list, then after each node is inserted (front or back) I display the nodes. When I do this, everything works fine with names without spaces, but if I use first and last with a space it does not function properly and will separate the string(s) with spaces into 2 different nodes, usually opposite of each other. Here is my code to read the data that is entered:

    struct node *new_node() {
    
        struct node *new1=(struct node *)malloc(sizeof(struct node));
    
        cin >> new1 -> string_val;
        new1 -> next=NULL;
    
        return new1;
    }

The constructor for the struct 'node' is as follows:

        struct node {
            char string_val[20];
            struct node *next;
        };

CodePudding user response：

Assuming the node definition needs to be the same and input is through stdin and all one one line for the following answer. Due to use of char [20] input from stdin is truncated to prevent overflow or segfault.

Given the following node (preserving OP's node definition):

struct node {
    char string_val[20];
    struct node *next;
};

Node can be constructed with following:

struct node *new_node() {
    // Create new node
    node * newNode = new node;

    // Get line
    std::cin.getline(newNode->string_val, 20);

    // Set next node to nullptr
    newNode->next = nullptr;

    return newNode;
}

If node definition can be changed and std::string can be used then this changes to the following:

#include <string>

struct node {
    std::string string_val;
    struct node *next;
};

struct node *new_node() {
    // Create new node
    struct node * newNode = new node;

    // Get line
    std::getline(std::cin, newNode->string_val);

    newNode->next = nullptr;

    return newNode;
}