Turn baud rate and the bit rate
Bradleychan read number: 2562018-09-24
Baud rate and the bit rate after they understand the writing a record, if there is a wrong, welcome to correct me, 1. The bit rate bit rate, as the name implies, is to transmit how much per unit time (bits), unit is a bit/s, baud rate is not bitrate, just sometimes, and bit rate are equal, (2) to understand the baud rate, coding will know coding (modulation), a simple example: the 01001111 series signal has eight (bits), if a a view, is that there are two different discrete values of 0 s and 1 s, but now suppose after modulation, we think every two bit now as a symbol () (o (symbols) to highlight), two is two, namely the string of signal look like this: 01 00 11 11, two by two, from only (high), before (low) level range (two different discrete values) into four different amplitude (four different discrete values) because (2 ^ 2=4) : 00 (minimum), 01 (low), 10 (high), 11 (highest), the word, binary people understand, did not explain, this series of signal becomes a (low) (minimum) (up) (up), although usually don't say so, generally speak four range of 0,1,2,3, then the signal becomes 1,0,3,3, 3. The baud rate baud rate, then what is? Is not, of course, how much per unit time transmitted bit (bit) - this is the bit rate, but how much per unit time transmission (symbol) (remember just focus on you), assumes that the bit rate is 8 b/s, which is a second transmission 8 bits, so in four kinds of amplitude is two to look at the two cases, the baud rate is how much? Namely pass how many symbols per second? Answer: 8 bits per second, per second pass 4 (symbol), as a symbol of two, how many people are in unit time transmission is uncertain, is not necessarily can determine how much a unit time transmission (symbol), can pass how many symbols, it depends on how to code, that is how we look at a string of signals, is a one or two of the two look, or three three watch? Thinking: or 01001111 this string of signals, bit rate or 8 b/s, namely a second pass eight, if we four four to see four) (that is, a symbol, and how much is the baud rate? (that is, can pass how many symbols per second), the answer: a four symbols, a second pass eight, so a second pass two symbols, 2=8/4, 4 bit rate and baud rate obtained the baud rate and bit rate are as follows: the relationship between bit rate=baud rate * (a), (if the bit rate is very simple, so baud rate is a according to the specific circumstances changing it rich bitch,) described up a bit odd, is not usually described in the formula, we usually described the formula slightly around a little bit of bending, is put (a symbol () several) replaced by log2 log2 (N) (N) (with 2 at the bottom, after all, is a binary stream), the N says there are several discrete values, and it is easy to understand, 2 (bottom) ^ (several) (a)=N, or clear example, such as a symbol for three, binary, a symbol to show 2 ^ 3=8 kinds of discrete values, a four symbols is 16 kinds of discrete values, five is a symbol of 32 kinds of discrete values... This formula became we usually see the: bit Rate=Baud Rate * log2 log2 (N) (N) 5. Porter and Baud Rate potter is not harry potter of the potter, are all the same, although the transliterated but this potter is Baud, because of the translation and Chinese, potter (Baud) itself has representative Rate, so the translation back not Baud Rate, but Baud, we give itself to add a Rate behind the potter (Rate) is presumably Chinese habit,