In Python I can do:
in_dd = {"aaa": 1, "bbb": 7, "zzz": 3, "hhh": 9, "ggg": 10, "ccc": 3}
out_ll = ['ggg', 'hhh', 'bbb', 'aaa', 'ccc', 'zzz']
so, I want to get keys sorted by value in descending order while having keys in ascending order taking into consideration sorted values
How can I do it in Scala?
In Scala I know I can do:
val m = Map("aaa" -> 3, "bbb" -> 7, "zzz" -> 3, "hhh" -> 9, "ggg" -> 10, "ccc" -> 3)
m.toSeq.sortWith(_._2 > _._2)
but I do not know how to sort by two cases.
EDIT:
I have tried also such approach but it does not return desired result:
m.toSeq.sortWith((x,y) => x._2 > y._2 && x._1 < y._1).map(_.1)
List((ggg,10), (hhh,9), (bbb,7), (ccc,3), (zzz,3), (aaa,3))
notice it shall be aaa,ccc,zzz
CodePudding user response:
In scala you could use:
m.toSeq.sortBy(a => (a._2, a._1) )(Ordering.Tuple2(Ordering.Int.reverse, Ordering.String.reverse))
for List((ggg,10), (hhh,9), (bbb,7), (zzz,3), (ccc,3), (aaa,3))
and
m.toSeq.sortBy(a => (-a._2, a._1) )
for List((ggg,10), (hhh,9), (bbb,7), (aaa,3), (ccc,3), (zzz,3))