How do i generate a string consisting of m number of rows and n number of cols, using random functio-CodePudding

Write a function named place_random_bricks(m, n, colours) that randomly places bricks row-wise (completes the current row placement before moving to the next row) on the baseplate.

It must have three parameters:

m - the number of rows on the base-plate,
n - the number of columns on the base-plate, and
colours - a random string constructed over “G, R, B, Y, C” (G-Green, R-Red, Blue-B, Y-Yellow, C-Cyan).

This function should return a string of length m * n, where a character at any position i represents the colour of a brick placed on the baseplate (0 ≤ i < (m x n), i ∈ “colours′′); a value “G” (Green colour) represents no brick was placed.

All colours have an equal probability of being selected.

import random
import colorama
import string

def place_random_bricks(m, n, colours):
    v_string=['G', 'R', 'B', 'Y', 'C']
    for i in range(m * n):
        colours = string.ascii_uppercase
        a = print(''.join(random.choices(colours)))

I am expecting a random number of RYBCG.

CodePudding user response：

I would recommend using numpy to generate random 2d arrays since. and the using a lookup string to convert those numbers to the list of random colours you want it to be converted to.

import numpy as np
def place_random_bricks(m,n, colors):
    ar = np.random.randint(0,len(colors),(m,n))
    return '\n'.join([''.join([colors[j] for j in i]) for i in ar])

print(place_random_bricks(4,5,['G','R','B','Y','C']))

CodePudding user response：

It seems odd that you wouldn't have to return an m*n matrix, but it clearly says it wants one string.

import random

def place_random_bricks(m, n, colours):
    row = [random.choice(colours) for _ in range(m*n)]
    return ''.join(row)

print(place_random_bricks(5,5,'GRBYC'))

Output:

GGYGYBBCBGYCCGYGCRRRCBGCB