Regex in Java - Match anything, except '*' character-CodePudding

Okay, so I'm trying to create a regex, that will ensure these 2 things:

String contains two '*'
String ends with 3 digits

I've made something, which kind of works, but it does not ensure that there are only 2 *, since in these spaces between the *, it can happen that there is another *:

Pattern.compile(".*\\*.*\\*[0-9]{3}", Pattern.CASE_INSENSITIVE);

So, these .* can be anything, any amount of characters, words and so on except * because I need to ensure that there are only 2 '*'.

How could I do it?

CodePudding user response：

[^*] matches anything but the * character so you could do

^(?:[^*]*\*){2}[^*]*\d{3}$

^ - start of line anchor
(?: - start of non-capturing group
- [^*]* - match zero or more non * characters
- \* - match on a *
) - end of non-capturing group
{2} - repeat this twice
[^*]* - matching only on non * characters
\d{3} - end with 3 digits
$ - end of line anchor

Demo

In a comment you added the constraint that it should end with * followed by 3 digits. That could be done by removing [^*]* after {2}

^(?:[^*]*\*){2}\d{3}$

Demo

CodePudding user response：

Try Following

^.*[\\*]{1}.*[\\*]{1}.*[0-9]{3}$

It ensure there are two * and end with 3 numbers