Python function does not accept the parameter-CodePudding

why does func2 not accept the parameter x?

def func1():
    x = 1
    return x

def func2(x):
    y = x 2
    print(y)

func2()

TypeError: func2() missing 1 required positional argument: 'x'

CodePudding user response：

You need to pass in a parameter when calling the function func2(), as this is what the function uses to perform the y = x 2 calculation. Without this parameter, the function wouldn't know what x is defined as in its local scope.

E.g func2(5) would print 7 as x would be 5 in func2's local scope.

CodePudding user response：

The func2() function is defined to accept a single argument, x, but no arguments are passed to it when it is called. As a result, an error is raised, because the function does not receive the x argument that it is expecting.

To fix this problem, you need to pass the x argument to the func2() function when you call it, like this:

x = 1 # or any number
func2(x)

CodePudding user response：

func2 accepts a parameter, but you haven't provided one.

If you want to pass it the value that func1 returned, you can assign func1's result to a variable, and then pass that variable as the argument to func2:

result = func1()  # call func1, assign result to a variable called "result"
func2(result)     # call func2 with that result as its argument

The x within func1 contains the value that is assigned to the variable result, and that same value is passed to func2 as its x parameter.

You can also skip the intermediate step of assigning a variable and just do:

func2(func1())  # call func2 with the result of func1() as its argument

CodePudding user response：

The code snippet when executed returns the Type Error: func2() missing 1 positional argument as when you defined func2 you made it compulsory to pass the argument x to func2 function (positional argument) and when the function call is made for func2() you have not passed the required argument.

If you are thinking that the value x that you defined inside the function func1() is not being accepted by func2. This is because the variable x is local variable and also you cannot pass the value to function while defining it. You pass the value to a function when you are calling it.

So if you want that the value x is should be accepted by func2 function you can write func2(func1) in place of func2().