Route::middleware(['auth', 'role:admin'])->name('admin.')->prefix('admin')->group(function(){
    Route::get('/role', [RoleController::class, 'index'])->name('index');
});

I want to user this route name. How I can?

              <li >
                <a href="{{ url('admin/role') }}" >
                  <i ></i>
                  <p>Roles</p>
                </a>
              </li>

user as url and it's working but I want to user the route name

CodePudding user response：

Instead of url() method ,use route().Here admin refers to ->name('admin.') and index refers to ->name('index')

<a href="{{ route('admin.index') }}" >

Ref: URLs For Named Routes

route method parameters

/**
     * Generate the URL to a named route.
     *
     * @param  array|string  $name
     * @param  mixed  $parameters
     * @param  bool  $absolute
     * @return string
     */
    function route($name, $parameters = [], $absolute = true)
    {
        return app('url')->route($name, $parameters, $absolute);
    }

CodePudding user response：

You can use route() function to get url based on its name. Keep in mind that the prefix wont change the name defined in route, so in your case the name will be "index", not "admin.index"

<a href="{{ route('index') }}" >

But it will be better if you use a more detailed route name to prevent overlapped of route name, Example :

// no need to use name() in grouping level
Route::middleware(['auth', 'role:admin'])->prefix('admin')->group(function(){
    Route::get('/role', [RoleController::class, 'index'])->name('admin.index'); // set the complete name here
});

so you will be able to call them with this :

<a href="{{ route('admin.index') }}" >

CodePudding user response：

Route::group(['prefix'=>'admin'], function(){

Route::resource('routename', ExampleController::class); });