CodePudding user response:
The eldest brother, roundingCodePudding user response:
Adoption of 27 mask 255.255.255.224CodePudding user response:
Define the subnet mask the steps as follows:A, determine which group address we use, for example, we apply to the network number is "210.73. A.", the network address as class c IP address, network identity as "210.73. A", the host are identified as "b",
B, according to our number of subnets required and may extend to the subnet number in the future, with some of the host machine to define the subnet mask, we need 12 subnets, for example, may need to be 16 in the future, the top four in the fourth byte determine the subnet mask, four are set to "1", namely to 4 bytes for "11110000", we may call this number new binary subnet mask,
C, every bit of the corresponding initial network set to "1", namely, the first three bytes are set to "1", the subnet mask of binary form is: "11111111.11111111.11111111.11110000,"
D, the number is converted into discontinuous decimal form is: "255.255.255.240."
CodePudding user response:
255.255.255.224CodePudding user response:
/27Alphanumeric patch
CodePudding user response:
"There is a class C network segment is a group of IP192.168.1.0/24, now you are asked to divide more than seven subnets, host addresses per subnet number shall not be less than 25 units, subnet mask for how many"The segment has 2 ^ 8-2=254 addresses are available, and now is divided into seven or more subnet, host addresses per subnet number shall not be less than 25 units, use the VLMS variable-length subnet mask: the original eight host is revised as follows: three network a + 5 host, it can be divided into 2 ^ 3=8 network, each network address available for 2 ^ 2=5-30 (Taiwan), meets the requirements, the subnet mask of 11111111, 11111111, 11111111, 11100000 (b)=255.255.255.224 (d)
CodePudding user response:
27 mask, hosts per subnet number is 30, meet the requirements of you is not less than 25 units,