while userInput in op and userInput != "q":
    score  = 1
    no_words  = 1
    userInput = input((str(no_words))   ". ").lower()

while userInput not in op and userInput != "q":
    score  = 0
    no_words  = 0
    print("Oops! Invalid input")
    userInput = input((str(no_words))   ". ").lower()

I expect when the user gives an input, my program will read through both these while loops each time in order to provide a correct output. ( I'm building a game which the users will need to list out as many words they can base on the origin word.)

for example: Extreme

1. tree
2. meet
3. ...
4. ...

Goal of the game: The more words user able to give, the higher the score will be.

CodePudding user response：

What you want to do is actually nest the condition within the loop.

Also, you'll never need to hardcode in " 0" to anything. if it doesn't change, you can simply leave out the line.

userInput = None
while userInput != 'q':
    userInput = input((str(no_words))   ". ").lower()
    if userInput in op:
       score  = 1
       no_words  = 1
    else:
       print('Oops! Invalid Input')
 

Edit: The important takeaway is that you can't run through two different while loops at the same time; the first one ends by the time the second one starts, until you get to some more advanced techniques. The solution is to figure out how to use a single while loop to access all the different paths of what could be happening at that moment.

CodePudding user response：

I think you're misunderstanding how to apply while loops. I think this solution would work in your case, however I don't entirely understand exactly what you are doing as some variables here were left out from your code sample. The logic should at least work.

while userInput != 'q':
    userInput = input((str(no_words))   ". ").lower()
    if userInput in op:
       score  = 1
       no_words  = 1
    else:
       score  = 0
       no_words  = 0
       

CodePudding user response：

Only 1 while-loop is needed, with if-conditions inside.
Also, I've added a list-comprehension to check that all letters are valid.
This game is quite fun.. try below code:

op = 'extreme'
print('Create as many words as possible (repeat letters are allowed) with this string:', op)
score = 0
inputList = []
userInput = ''

while userInput != 'q':
    userInput = input('Words created {}:'.format(inputList)).lower()
    if all([e in list(op) for e in list(userInput)]) and userInput not in inputList:
        score  = 1
        inputList.append(userInput)
    elif userInput != 'q':
        print('Oops! Invalid input')
    
print('Your final score:', score)

Expected output

Create as many words as possible (repeat letters are allowed) with this string: extreme
Words created []: met
Words created ['met']: met
Oops! Invalid input
Words created ['met']: tree
Words created ['met', 'tree']: team
Oops! Invalid input
Words created ['met', 'tree']: q
Your final score: 2