Compare and eliminate repeating values in the dictionary-CodePudding

I have a dictionary as follows:

dict = {'alpha1': ['a', 'b', 'c', 'd', 'e', 'f'], 'alpha2': ['e', 'f', 'g'], 'alpha3': ['j', 'k', 'l', 'm'], 'alpha4': ['h', 'i', 'j', 'k']}

Is it possible to compare the values in the dictionary to ensure that each value appears only one time. I need to eliminate the repeating values so that I can have a dictionary like this:

dict = {'alpha1': ['a', 'b', 'c', 'd', 'e', 'f'], 'alpha2': ['g'], 'alpha3': ['j', 'k', 'l', 'm'], 'alpha4': ['h', 'i']}

I am trying the following:

result = {}
for key, value in dict.items():
    if value not in result.values():
        result[key] = value
print(result)

This is returning the same original dictionary to me. I am quite new to python so any help will be appreciated.

CodePudding user response：

You need to loop over the list elements, and test each string to see if it has been added to any of the lists.

You can use a set to keep all the strings that have been added.

result = {}
seen = set()

for key, value in dict.items():
    for string in value:
        if string not in seen:
            seen.add(string)
            result.setdefault(key, []).append(string)

print(result)

BTW, don't use dict as a variable name. It's already a built-in type.