Small white when doing the Proteus simulation, buzzer how also not ring, ask everybody to help solve the

 
Void xianshi () 
{
TR0=0; 
Num=0; 
Sp=1; 
delay(100); 
Sp=0; 
While (1) 
{
for(a=0; a<4. +) 
{
Delay (5); 
The P2=table0 [a]; 
P0=table [display [a]]; 
} 
The display [0]=num/10; 
The display [1]=num % 10; 
The display [2]=num1/10; 
The display [3]=num1%10; 
If (k4==0) 
{
Num=num2; 
Num1=0; 
TR0=1; 
L1=1; 
L2=1; 
return; 
} 
} 
} 


Void main () 
{
L1=1; 
L2=1; 
Sp=0; 
X=0; 
Num=num2=30; 
While (1) 
{
If (x==1) 
{
Delay (5); 
TR0=1; 
While (1) 
{
Keyboad (); 
If (k4==0) 
{
L1=1; 
L2=1; 
Delay (5); 
Num=num2; 
TR0=1; 
} 
} 
} 
The else 
{
for(a=0; a<4. +) 
{
Delay (5); 
The P2=table0 [a]; 
P0=table [display [a]]; 
} 
The display [0]=num/10; 
The display [1]=num % 10; 
The display [2]=num1/10; 
The display [3]=num1%10; 
The init (); 
} 
} 
} 
Void time0 () interrupt 1 
{
TH0=(65536-10000)/256; 
TL0=(65536-10000)%256; 
count++; 
If (k4==0) 
{
Num=num2; 
TR0=1; 
Num1=0; 
return; 
} 
for(a=0; a<4. +) 
{
Delay (10); 
The P2=table0 [a]; 
P0=table [display [a]]; 
} 
The display [0]=num/10; 
The display [1]=num % 10; 
The display [2]=num1/10; 
The display [3]=num1%10; 
If (count==100) 
{
Count=0; 
Num -; 
If (num<5) 
{
L1=~ l1. 
Sp=1; 
Delay (200); 
Sp=0; 
If (num==0) 
{
L1=0; 
Sp=0; Delay (200); Sp=1; 
delay(100); 
Sp=0; Delay (200); Sp=1; 
delay(100); 
Sp=0; Delay (200); Sp=1; 
} 
If (num==0) 
{
While (1) 
{
Xianshi (); 
If (k4==0) 
{
L1=1; 
L2=1; 
Num=num2; 
TR0=1; 
return; 
} 
} 
} 
} 
} 
X2 + +; 
If (x2==4) 
{
X2=0; 
} 
P3=table2 (x2), }

CodePudding user response:

You look at the buzzer, a head of the network of the triangle symbol is ground or power supply

CodePudding user response:

//active or passive buzzer?
//if it is a passive buzzer, the need to produce a pulse on the buzzer is about 2 k

CodePudding user response:

Program also didn't see you inside drive P14 the IO, the frequency of the driver should be around 3 k right, of course also can be 2 k, the characteristics of the buzzer frequency is generally 2 k or 4 k, so use about 3 k can juggle two buzzer,

CodePudding user response:

More than 1 KHZ frequency input