I want to change the priority of the preprocessor define process.
see the following code:
#include <iostream>
#include <sstream>
#define $(x) << x <<
#define f(x) (#x)
int main()
{
auto world = "universe!";
std::stringstream ss;
ss << f(Hello $(world)) << std::endl;
std::cout << ss.str();
return 0;
}
The code run, but the 'f' macro will always processed before the '$' macro.
The current output:
Hello $(world)
Expected output:
Hello universe!
Thx.
CodePudding user response:
"Solving" the problem:
#include <iostream>
#include <sstream>
#define $(x) << " " << x
#define STRINGIFY(x) #x
#define TOSTRING(x) STRINGIFY(x)
#define f(x, y) TOSTRING(x) y
int main()
{
auto world = "universe!";
std::stringstream ss;
ss << f(Hello, $(world)) << std::endl;
std::cout << ss.str();
return 0;
}
Output:
Hello universe!
CodePudding user response:
You might "delay" expansion with extra indirection:
#define $(x) << x <<
#define STRINGIFY(x) #x
#define f(x) STRINGIFY(x)
but you won't get your expected result but Hello << world <<
Demo
Without changing your MACRO, you might already get your result by "fixing" your parenthesis (and surrounding):
ss << f(Hello) " " $(world) /*<<*/ std::endl;
Demo.