I have a user table with the fields id
and email
(among others). The email address isn't case insensitive, a problem we want to fix, but we have some duplicate values in there (duplicate except the case, so currently we have [email protected]
and [email protected]
in there). I am now trying to get an overview of all the duplicate accounts, but this query is just taking forever, I had to cancel it after 5 minutes. The table has about 250.000 records.
select * from user u1
where (select count(*) from user u2
where LOWER(u1.email) = LOWER(u2.email)) > 1
I am finding plenty of examples to find literal duplicate records, but nothing for case-insensitive duplicates. Any ideas?
CodePudding user response:
You can use the having
clause. Should be faster than the inner clause
select lower(email)
from test
group by lower(email)
having count(*)>1