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Assemble a small problem

Time:10-19

Memory information is: b82266 but why mov axy, 6622 h?

CodePudding user response:

Memory information? Is instruction code, compiled the book has instruction code interpretation, B8 is to immediately give instruction + RRR registers domain, the rest is just a corresponding number immediately,

CodePudding user response:

Your memory information is as follows:
B8
22
66
Immediately behind and then mov axy, 6622 h, 6622 h, low is 22, high is 66, in the memory is:
22
66
So to understand, is that memory is from low to high, from low to high addresses direction to write information,
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