I'm trying to covert the following array to a Map:
const arr = [
{ key: 'user1', value: { num: 0, letter: 'a' } },
{ key: 'user2', value: { num: 0, letter: 'b' } },
{ key: 'user3', value: { num: 0, letter: 'c' } },
];
What I have so far:
const arr = [
{ key: 'user1', value: { num: 0, letter: 'a' } },
{ key: 'user2', value: { num: 0, letter: 'b' } },
{ key: 'user3', value: { num: 0, letter: 'c' } },
];
const b = arr.map(obj => [obj.key, obj.value]);
const map = new Map<string, { num: number; letter: string }>(b);
console.log(map.get('user1'));
Do you know if this is something achievable?
PS: You can find Typescript playground here and the error that I'm getting
CodePudding user response:
obj.key
is a string
, and obj.value
is a {num: number, letter: string}
, so if you make an array of them ([obj.key, obj.value]
), then you get an Array<string | {num: number, letter: string}>
.
You need to tell TypeScript that you're creating a specific tuple, as expected by the Map constructor, not a generic array. There are a few ways of doing this:
// The simplest: Tell TypeScript "I mean exactly what I said."
// (This makes it readonly, which isn't always desirable.)
const b = arr.map(obj => [obj.key, obj.value] as const);
// Or be explicit in a return type. You can do this at a few levels.
const b = arr.map<[string, { num: number, letter: string}]>(obj => [obj.key, obj.value]);
const b = arr.map((obj): [string, { num: number, letter: string}] => [obj.key, obj.value]);
// Or, as explained in the comments, do it in one line, and TypeScript
// can infer tuple vs. array itself.
const map = new Map(arr.map(obj => [obj.key, obj.value]));